H(1)=-4.9t^2+70

Solution for H(1)=-4.9t^2+70 equation:

(1)=-4.9H^2+70

We move all terms to the left:

(1)-(-4.9H^2+70)=0

We get rid of parentheses

4.9H^2-70+1=0

We add all the numbers together, and all the variables

4.9H^2-69=0

a = 4.9; b = 0; c = -69;
Δ = b2-4ac
Δ = 02-4·4.9·(-69)
Δ = 1352.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1352.4}}{2*4.9}=\frac{0-\sqrt{1352.4}}{9.8}
=-\frac{\sqrt{}}{9.8}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1352.4}}{2*4.9}=\frac{0+\sqrt{1352.4}}{9.8}
=\frac{\sqrt{}}{9.8}
$